Optimal. Leaf size=150 \[ \frac {b^2 (2 A b+5 a B) \sqrt {x} \sqrt {a+b x}}{a}-\frac {2 b (2 A b+5 a B) (a+b x)^{3/2}}{3 a \sqrt {x}}-\frac {2 (2 A b+5 a B) (a+b x)^{5/2}}{15 a x^{3/2}}-\frac {2 A (a+b x)^{7/2}}{5 a x^{5/2}}+b^{3/2} (2 A b+5 a B) \tanh ^{-1}\left (\frac {\sqrt {b} \sqrt {x}}{\sqrt {a+b x}}\right ) \]
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Rubi [A]
time = 0.05, antiderivative size = 150, normalized size of antiderivative = 1.00, number of steps
used = 7, number of rules used = 6, integrand size = 20, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.300, Rules used = {79, 49, 52, 65,
223, 212} \begin {gather*} b^{3/2} (5 a B+2 A b) \tanh ^{-1}\left (\frac {\sqrt {b} \sqrt {x}}{\sqrt {a+b x}}\right )+\frac {b^2 \sqrt {x} \sqrt {a+b x} (5 a B+2 A b)}{a}-\frac {2 (a+b x)^{5/2} (5 a B+2 A b)}{15 a x^{3/2}}-\frac {2 b (a+b x)^{3/2} (5 a B+2 A b)}{3 a \sqrt {x}}-\frac {2 A (a+b x)^{7/2}}{5 a x^{5/2}} \end {gather*}
Antiderivative was successfully verified.
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Rule 49
Rule 52
Rule 65
Rule 79
Rule 212
Rule 223
Rubi steps
\begin {align*} \int \frac {(a+b x)^{5/2} (A+B x)}{x^{7/2}} \, dx &=-\frac {2 A (a+b x)^{7/2}}{5 a x^{5/2}}+\frac {\left (2 \left (A b+\frac {5 a B}{2}\right )\right ) \int \frac {(a+b x)^{5/2}}{x^{5/2}} \, dx}{5 a}\\ &=-\frac {2 (2 A b+5 a B) (a+b x)^{5/2}}{15 a x^{3/2}}-\frac {2 A (a+b x)^{7/2}}{5 a x^{5/2}}+\frac {(b (2 A b+5 a B)) \int \frac {(a+b x)^{3/2}}{x^{3/2}} \, dx}{3 a}\\ &=-\frac {2 b (2 A b+5 a B) (a+b x)^{3/2}}{3 a \sqrt {x}}-\frac {2 (2 A b+5 a B) (a+b x)^{5/2}}{15 a x^{3/2}}-\frac {2 A (a+b x)^{7/2}}{5 a x^{5/2}}+\frac {\left (b^2 (2 A b+5 a B)\right ) \int \frac {\sqrt {a+b x}}{\sqrt {x}} \, dx}{a}\\ &=\frac {b^2 (2 A b+5 a B) \sqrt {x} \sqrt {a+b x}}{a}-\frac {2 b (2 A b+5 a B) (a+b x)^{3/2}}{3 a \sqrt {x}}-\frac {2 (2 A b+5 a B) (a+b x)^{5/2}}{15 a x^{3/2}}-\frac {2 A (a+b x)^{7/2}}{5 a x^{5/2}}+\frac {1}{2} \left (b^2 (2 A b+5 a B)\right ) \int \frac {1}{\sqrt {x} \sqrt {a+b x}} \, dx\\ &=\frac {b^2 (2 A b+5 a B) \sqrt {x} \sqrt {a+b x}}{a}-\frac {2 b (2 A b+5 a B) (a+b x)^{3/2}}{3 a \sqrt {x}}-\frac {2 (2 A b+5 a B) (a+b x)^{5/2}}{15 a x^{3/2}}-\frac {2 A (a+b x)^{7/2}}{5 a x^{5/2}}+\left (b^2 (2 A b+5 a B)\right ) \text {Subst}\left (\int \frac {1}{\sqrt {a+b x^2}} \, dx,x,\sqrt {x}\right )\\ &=\frac {b^2 (2 A b+5 a B) \sqrt {x} \sqrt {a+b x}}{a}-\frac {2 b (2 A b+5 a B) (a+b x)^{3/2}}{3 a \sqrt {x}}-\frac {2 (2 A b+5 a B) (a+b x)^{5/2}}{15 a x^{3/2}}-\frac {2 A (a+b x)^{7/2}}{5 a x^{5/2}}+\left (b^2 (2 A b+5 a B)\right ) \text {Subst}\left (\int \frac {1}{1-b x^2} \, dx,x,\frac {\sqrt {x}}{\sqrt {a+b x}}\right )\\ &=\frac {b^2 (2 A b+5 a B) \sqrt {x} \sqrt {a+b x}}{a}-\frac {2 b (2 A b+5 a B) (a+b x)^{3/2}}{3 a \sqrt {x}}-\frac {2 (2 A b+5 a B) (a+b x)^{5/2}}{15 a x^{3/2}}-\frac {2 A (a+b x)^{7/2}}{5 a x^{5/2}}+b^{3/2} (2 A b+5 a B) \tanh ^{-1}\left (\frac {\sqrt {b} \sqrt {x}}{\sqrt {a+b x}}\right )\\ \end {align*}
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Mathematica [A]
time = 0.27, size = 100, normalized size = 0.67 \begin {gather*} -\frac {\sqrt {a+b x} \left (b^2 x^2 (46 A-15 B x)+2 a^2 (3 A+5 B x)+2 a b x (11 A+35 B x)\right )}{15 x^{5/2}}-b^{3/2} (2 A b+5 a B) \log \left (-\sqrt {b} \sqrt {x}+\sqrt {a+b x}\right ) \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 0.08, size = 206, normalized size = 1.37
method | result | size |
risch | \(-\frac {\sqrt {b x +a}\, \left (-15 b^{2} B \,x^{3}+46 A \,b^{2} x^{2}+70 B a b \,x^{2}+22 a A b x +10 a^{2} B x +6 a^{2} A \right )}{15 x^{\frac {5}{2}}}+\frac {\left (A \ln \left (\frac {\frac {a}{2}+b x}{\sqrt {b}}+\sqrt {b \,x^{2}+a x}\right ) b^{\frac {5}{2}}+\frac {5 B \ln \left (\frac {\frac {a}{2}+b x}{\sqrt {b}}+\sqrt {b \,x^{2}+a x}\right ) b^{\frac {3}{2}} a}{2}\right ) \sqrt {\left (b x +a \right ) x}}{\sqrt {b x +a}\, \sqrt {x}}\) | \(141\) |
default | \(\frac {\sqrt {b x +a}\, \left (30 A \ln \left (\frac {2 \sqrt {\left (b x +a \right ) x}\, \sqrt {b}+2 b x +a}{2 \sqrt {b}}\right ) b^{3} x^{3}+75 B \ln \left (\frac {2 \sqrt {\left (b x +a \right ) x}\, \sqrt {b}+2 b x +a}{2 \sqrt {b}}\right ) a \,b^{2} x^{3}+30 B \,b^{\frac {5}{2}} \sqrt {\left (b x +a \right ) x}\, x^{3}-92 A \,b^{\frac {5}{2}} \sqrt {\left (b x +a \right ) x}\, x^{2}-140 B \,b^{\frac {3}{2}} \sqrt {\left (b x +a \right ) x}\, a \,x^{2}-44 A a \,b^{\frac {3}{2}} x \sqrt {\left (b x +a \right ) x}-20 B \,a^{2} x \sqrt {b}\, \sqrt {\left (b x +a \right ) x}-12 A \,a^{2} \sqrt {b}\, \sqrt {\left (b x +a \right ) x}\right )}{30 x^{\frac {5}{2}} \sqrt {\left (b x +a \right ) x}\, \sqrt {b}}\) | \(206\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [B] Leaf count of result is larger than twice the leaf count of optimal. 244 vs.
\(2 (120) = 240\).
time = 0.28, size = 244, normalized size = 1.63 \begin {gather*} \frac {5}{2} \, B a b^{\frac {3}{2}} \log \left (2 \, b x + a + 2 \, \sqrt {b x^{2} + a x} \sqrt {b}\right ) + A b^{\frac {5}{2}} \log \left (2 \, b x + a + 2 \, \sqrt {b x^{2} + a x} \sqrt {b}\right ) - \frac {35 \, \sqrt {b x^{2} + a x} B a b}{6 \, x} - \frac {38 \, \sqrt {b x^{2} + a x} A b^{2}}{15 \, x} - \frac {5 \, \sqrt {b x^{2} + a x} B a^{2}}{6 \, x^{2}} - \frac {7 \, \sqrt {b x^{2} + a x} A a b}{30 \, x^{2}} - \frac {5 \, {\left (b x^{2} + a x\right )}^{\frac {3}{2}} B a}{6 \, x^{3}} + \frac {3 \, \sqrt {b x^{2} + a x} A a^{2}}{10 \, x^{3}} - \frac {{\left (b x^{2} + a x\right )}^{\frac {3}{2}} A b}{3 \, x^{3}} + \frac {{\left (b x^{2} + a x\right )}^{\frac {5}{2}} B}{x^{4}} - \frac {{\left (b x^{2} + a x\right )}^{\frac {3}{2}} A a}{2 \, x^{4}} - \frac {{\left (b x^{2} + a x\right )}^{\frac {5}{2}} A}{5 \, x^{5}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 1.13, size = 217, normalized size = 1.45 \begin {gather*} \left [\frac {15 \, {\left (5 \, B a b + 2 \, A b^{2}\right )} \sqrt {b} x^{3} \log \left (2 \, b x + 2 \, \sqrt {b x + a} \sqrt {b} \sqrt {x} + a\right ) + 2 \, {\left (15 \, B b^{2} x^{3} - 6 \, A a^{2} - 2 \, {\left (35 \, B a b + 23 \, A b^{2}\right )} x^{2} - 2 \, {\left (5 \, B a^{2} + 11 \, A a b\right )} x\right )} \sqrt {b x + a} \sqrt {x}}{30 \, x^{3}}, -\frac {15 \, {\left (5 \, B a b + 2 \, A b^{2}\right )} \sqrt {-b} x^{3} \arctan \left (\frac {\sqrt {b x + a} \sqrt {-b}}{b \sqrt {x}}\right ) - {\left (15 \, B b^{2} x^{3} - 6 \, A a^{2} - 2 \, {\left (35 \, B a b + 23 \, A b^{2}\right )} x^{2} - 2 \, {\left (5 \, B a^{2} + 11 \, A a b\right )} x\right )} \sqrt {b x + a} \sqrt {x}}{15 \, x^{3}}\right ] \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A]
time = 40.34, size = 201, normalized size = 1.34 \begin {gather*} A \left (- \frac {2 a^{2} \sqrt {b} \sqrt {\frac {a}{b x} + 1}}{5 x^{2}} - \frac {22 a b^{\frac {3}{2}} \sqrt {\frac {a}{b x} + 1}}{15 x} - \frac {46 b^{\frac {5}{2}} \sqrt {\frac {a}{b x} + 1}}{15} - b^{\frac {5}{2}} \log {\left (\frac {a}{b x} \right )} + 2 b^{\frac {5}{2}} \log {\left (\sqrt {\frac {a}{b x} + 1} + 1 \right )}\right ) + B \left (- \frac {2 a^{2} \sqrt {b} \sqrt {\frac {a}{b x} + 1}}{3 x} - \frac {14 a b^{\frac {3}{2}} \sqrt {\frac {a}{b x} + 1}}{3} - \frac {5 a b^{\frac {3}{2}} \log {\left (\frac {a}{b x} \right )}}{2} + 5 a b^{\frac {3}{2}} \log {\left (\sqrt {\frac {a}{b x} + 1} + 1 \right )} + b^{\frac {5}{2}} x \sqrt {\frac {a}{b x} + 1}\right ) \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F(-2)]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Exception raised: NotImplementedError} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.01 \begin {gather*} \int \frac {\left (A+B\,x\right )\,{\left (a+b\,x\right )}^{5/2}}{x^{7/2}} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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